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A person speaking normally produces a sound intensity of `40 dB` at a distance of `1 m`. If the threshold intensity for reasonable audibility is `20 dB`, the maximum distance at which he can be heard cleary is.A. `4 m`B. `5 m`C. `10 m`D. `20 m` |
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Answer» Correct Answer - C `L_(1) - L_(2) = 10 log_(10) ((I_(1))/(I_(2))) =10 log_(10) ((r_(2)^(2))/(r_(1)^(2)))` `40 - 20 = 10 log_(10) ((r_(2))/(r_(1)^(2)))` `20 = 20 log_(10) ((r_(2))/(r_(1)))` `log_(10)((r_(2))/(r_(1))) = 1 rArr (r_(2))/(r_(1)) = 10` ` r_(2) = 10 r_(1) = 10 m` |
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