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A Person Takes 20 Minutes More To Cover A Certain Distance By Decreasing His Speed By 20%. What Is The Time Taken To Cover The Distance At His Original Speed ? |
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Answer» Let the distance and ORIGINAL speed be 'd' km and 'k' kmph RESPECTIVELY. d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3 => (5d - 4d)/4k = 1/3 => d = 4/3 k TIME TAKEN to cover the distance at original speed = d/k = 4/3 hours = 1 hour 20 minutes. Let the distance and original speed be 'd' km and 'k' kmph respectively. d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3 => (5d - 4d)/4k = 1/3 => d = 4/3 k Time taken to cover the distance at original speed = d/k = 4/3 hours = 1 hour 20 minutes. |
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