A Person Travels In A Car With Uniform Speed. He Observes The Milesto

1.	A Person Travels In A Car With Uniform Speed. He Observes The Milestone,which Has 2 Digits. After One Hour He Observes Another Milestone With Same Digits Reversed. After Another Hour He Observes Another Milestone With Same 2 Digits Separated By 0. Find The Speed Of The Car?
Answer» Let 10'splace digit is x and UNIT's PLACE digit y First milestone : 10x+y Second milestone : 10y+x Third milestone: 100x+y Since the speed is uniform so DISTANCE covered in first Hr = Distance covered in Second Hr (10y+x)-(10x+y) = (100x+y)-(10y+x) By SOLVING, y=6x but since x and y are digits so only possible combination is x=1 and y=6, So average speed = 45 KMPH. Let 10'splace digit is x and unit's place digit y First milestone : 10x+y Second milestone : 10y+x Third milestone: 100x+y Since the speed is uniform so Distance covered in first Hr = Distance covered in Second Hr (10y+x)-(10x+y) = (100x+y)-(10y+x) By solving, y=6x but since x and y are digits so only possible combination is x=1 and y=6, So average speed = 45 Kmph.

A Person Travels In A Car With Uniform Speed. He Observes The Milestone,which Has 2 Digits. After One Hour He Observes Another Milestone With Same Digits Reversed. After Another Hour He Observes Another Milestone With Same 2 Digits Separated By 0. Find The Speed Of The Car?

Answer»

Let 10'splace digit is x and UNIT's PLACE digit y

First milestone : 10x+y

Second milestone : 10y+x

Third milestone: 100x+y

Since the speed is uniform so

DISTANCE covered in first Hr = Distance covered in Second Hr

(10y+x)-(10x+y) = (100x+y)-(10y+x)

y=6x

but since x and y are digits so only possible combination is x=1 and y=6,

So average speed = 45 KMPH.

Let 10'splace digit is x and unit's place digit y