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If Each Of The Three Nonzero Numbers A , B , And C Is Divisible By 3, Then Abc Must Be Divisible By Which One Of The Following The Number?

Answer»

Since each one of the three numbers a, b, and c is divisible by 3, the numbers can be represented as 3P,3q, and 3r, RESPECTIVELY, where p, q, and r are INTEGERS.

The PRODUCT of the three numbers is 3p*3q*3r =27(pqr).

Since p, q, and r are integers, pqr is an integer and THEREFORE abc is divisible by 27.

Since each one of the three numbers a, b, and c is divisible by 3, the numbers can be represented as 3p,3q, and 3r, respectively, where p, q, and r are integers.

The product of the three numbers is 3p*3q*3r =27(pqr).

Since p, q, and r are integers, pqr is an integer and therefore abc is divisible by 27.



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