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a perticles start from the rest and moves with constant acceleration of 0.5ms^-2. calculate the time taken by the particles to cover a distance. |
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Answer» Answer: u=0,v=18 km/hr=5 m/s,t=5 sec a= t v−u
= 5 5−0
=1 m/s 2
s=ut+ 2 1
at 2 =12.5 m/s 2
(a) Average velocity V
=(12.5)/5=2.5 m/s (b) Distance TRAVELLED is 12.5 m. Explanation: FOLLOW now |
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