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A piano wire having a diameter of `0.90 mm` is replaced by another wire of the same material but with a diameter of `0.93 mm`.If the tension of the wire is kept the same , then the percentage change in the frequency of the fundamental tone isA. 0.03B. 0.003C. `+3.2%`D. `-3.26%` |
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Answer» Correct Answer - D `d_1=0.90mm, d_2 = 0.93 mm` `n_1 prop 1/d_1 " and " n_2 prop 1/d_2` `(n_2)/(n_1) - 1= (d_1)/(d_2) -1 = 90/93-1` `therefore (n_2-n_1)/(n_1) xx100 = ((90-93)/(93)) 100 = (-3)/(93) xx100` `(n_2-n_1)/(n_1)% = (-1)/(31) xx100 = -0.0326xx100` =-3.26% |
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