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A pipe `30.0` cm long is opened at both ends. Which Harmonic mode of the pipe will be at `1.1` kHz frequency also find fundamental frequency, if one end of the pipe is colsed. Take the speed of sound in air as 330 `"ms"^(-1)`A. 2nd harmonic and 275 HzB. 1st harmonic and 260 HzC. 3rd harmonic and 260 HzD. Fundamental harmonic and 240 Hz |
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Answer» Correct Answer - a Here, `L = 30.0` cm `=0.3` cm Let, nth harmonic of open pipe is at a frequency of 1 kHz, i.e. `v_(n) = 1.1" kHz"= 1100` Hz As, `v_(n) = (nv)/(2L)` `therefore n =(2Lv_(n))/v=(2xx0.30xx1100)/330=2` i.e. 2nd harmonic of the open pipe will present. If one end of pipe is closed, its fundamental frequency `n=0" in " v_(0)=(2n+1)v/(4L)` ` v_(1)=v/(4L)=330/(4xx0.3)=275` Hz |
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