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A point charge of +8μC cxperiences a force of 2000 N at a point, what is the electric fieldintensity at that point ?a ioC ura tnaratod by a distance of 20 cmm. What is the E at a point |
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Answer» The intensity at the given point will be E=F/ q ; So from the given formula the intensity of the given point will be E= 2000/8*10^-6; Which is equal to E= 2.5 *10^8 Newton/coulomb; |
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