1.

A point charge of +8μC cxperiences a force of 2000 N at a point, what is the electric fieldintensity at that point ?a ioC ura tnaratod by a distance of 20 cmm. What is the E at a point

Answer»

The intensity at the given point will be

E=F/ q ;

So from the given formula the intensity of the given point will be

E= 2000/8*10^-6;

Which is equal to

E= 2.5 *10^8 Newton/coulomb;



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