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A point initially at rest moves along x-axis. Its acceleration varies with time as `a = (6t + 5) m//s^(2)`. If it starts from origin, the distance covered in 2 s is:A. 20 mB. 28 mC. 16 mD. 25 m |
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Answer» Correct Answer - B `(dv)/(dt) = (6t + 5)` `int_(0)^(v) dv = (6t^(2))/(2) + 5t` `v = 3 t^(2) + 5t` `(dx)/(dt) = 3 t^(2) + 5t` `x = t^(3) + 5 t^(2)` |
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