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A point move in straight line so that its displacement x m at time t sec is given byx-1+t. itsacceleration in m/sec at a time t sec is[21] |
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Answer» x^2=t^2+1 taking its differentiation, 2x*(dx/dt)=2t x*(dx/dt)=t again taking differentiation for acceleration, x*(d^2x/dt^2) + (dx/dt)^2= 1 x*(d^2x/dt^2) = 1 –(dx/dt)^2 x*(d^2x/dt^2) = 1 – (t/x)^2 (becausex*(dx/dt)=t) (d^2x/dt^2) = (1 – (t/x)^2)/x (d^2x/dt^2) = 1/x – t^2/x^3 put t2= x2-1 (d2x/dt2) = 1/x3 tarun how can you give the answer in terms of x |
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