1.

A point move in straight line so that its displacement x m at time t sec is given byx-1+t. itsacceleration in m/sec at a time t sec is[21]

Answer»

x^2=t^2+1

taking its differentiation,

2x*(dx/dt)=2t

x*(dx/dt)=t

again taking differentiation for acceleration,

x*(d^2x/dt^2) + (dx/dt)^2= 1

x*(d^2x/dt^2) = 1 –(dx/dt)^2

x*(d^2x/dt^2) = 1 – (t/x)^2 (becausex*(dx/dt)=t)

(d^2x/dt^2) = (1 – (t/x)^2)/x

(d^2x/dt^2) = 1/x – t^2/x^3

put t2= x2-1

(d2x/dt2) = 1/x3

tarun how can you give the answer in terms of x



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