A point source of power `50pi` watts is producing sound waves of frequency `1875Hz`. The velocity of sound is `330m//s`, atmospheric pressure is `1.0xx10^(5)Nm^(-2)`, density of air is `(400)/(99pi)kgm^-3`. Then the displacement amplitude at `r=sqrt(330)`m from the point source isA. `0.5mum`B. `0.2mum`C. `1mum`D. `2mum`

A point source of power `50pi` watts is producing sound waves of frequ

1.	A point source of power `50pi` watts is producing sound waves of frequency `1875Hz`. The velocity of sound is `330m//s`, atmospheric pressure is `1.0xx10^(5)Nm^(-2)`, density of air is `(400)/(99pi)kgm^-3`. Then the displacement amplitude at `r=sqrt(330)`m from the point source isA. `0.5mum`B. `0.2mum`C. `1mum`D. `2mum`
Answer» Correct Answer - C `P_0=BKS`, `k=(2pi)/(lamda)`, `lamda=(v)/(f)`, `v=sqrt((B)/(rho))` Using above, we get `S_0=(P_0)/(2rhovpif)=(5)/(2xx1xx330xx3.14xx1875)` `=1mu` meter

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