A police car travels towards a stationaryobserver at a speed of 15 m/s

1.	A police car travels towards a stationaryobserver at a speed of 15 m/s. The sirenon the car emits a sound of frequency 250Hz. Calculate the recorded frequency.The speed of sound is 340 m/s.
Answer» Question :- A police car TRAVELS towards a stationary observer at a speed of 15 m/s. The siren on the car emits a sound of frequency 250 Hz. Calculate the recorded frequency. The speed of sound is 340 m/s. Answer :- The frequency HEARD by the audience as the car approaches stand is 261.54Hz. Step by step explanation :- Given : $\bullet\sf\:{v_s = 15m/s} \\ \\\bullet\sf\:{n_0 = 250Hz} \\ \\ \bullet\sf\:{v= 340m/s}$ Need to find : Frequency (n) Formula : $\bigstar\: \sf{n = n_0 \bigg( \frac{v}{v - v_s} \bigg)} \\$ ⏩ As the source approaches LISTENER, APPARENT frequency is given by, $\sf:\longmapsto{n =250 \bigg( \frac{340}{340 - 15} \bigg) } \\ \\ \sf:\longmapsto{n = 250 \bigg( \frac{340}{325} \bigg) } \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{n = 250 \bigg( \frac{68}{65} \bigg)} \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{n = \frac{17000}{65} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf:\longmapsto \red{n = 261.54} \: \: \: \: \: \: \: \: \: \: \: \: \:$ ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Learn more from brainly : The sound EMITTED from the siren of an ambulance has frequency of 1500 HZ The speed of sound is 340 m/s. Calculate the difference in frequencies heard by a stationary observer it the ambulance initially. travels towards and then away from the observer at a speed of 30 m/s. brainly.in/question/13239279

A police car travels towards a stationaryobserver at a speed of 15 m/s. The sirenon the car emits a sound of frequency 250Hz. Calculate the recorded frequency.The speed of sound is 340 m/s.

Answer»

Question :-

A police car TRAVELS towards a stationary

observer at a speed of 15 m/s. The siren

on the car emits a sound of frequency 250

Hz. Calculate the recorded frequency.

The speed of sound is 340 m/s.

Answer :-

The frequency HEARD by the audience as the car approaches stand is 261.54Hz.

Step by step explanation :-

Given :

$\bullet\sf\:{v_s = 15m/s} \\ \\\bullet\sf\:{n_0 = 250Hz} \\ \\ \bullet\sf\:{v= 340m/s}$

Need to find :

Frequency (n)

Formula :

$\bigstar\: \sf{n = n_0 \bigg( \frac{v}{v - v_s} \bigg)} \\$

⏩ As the source approaches LISTENER, APPARENT frequency is given by,

$\sf:\longmapsto{n =250 \bigg( \frac{340}{340 - 15} \bigg) } \\ \\ \sf:\longmapsto{n = 250 \bigg( \frac{340}{325} \bigg) } \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{n = 250 \bigg( \frac{68}{65} \bigg)} \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{n = \frac{17000}{65} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf:\longmapsto \red{n = 261.54} \: \: \: \: \: \: \: \: \: \: \: \: \:$

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Learn more from brainly :

The sound EMITTED from the siren of an

ambulance has frequency of 1500 HZ

The speed of sound is 340 m/s. Calculate

the difference in frequencies heard by

a stationary observer it the ambulance

initially. travels towards and then away

from the observer at a speed of 30 m/s.

brainly.in/question/13239279