A potential drop per unit length along a wire is 5 × 10-3 V/m. If the – InterviewSolution

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1.

A potential drop per unit length along a wire is 5 × 10-3 V/m. If the emf of a cell balances against length 216 cm of this potentiometer wire, find the emf of the cell.

Answer»

Data: K = 5 × 10^-3 V/m , L = 216 cm = 216 × 10^-2 m

E = KL

∴ E = 5 × 10^-3 × 216 × 10^-2

= 1080 × 10^-5

= 0.01080V

The emf of the cell is 0.01080 volt.

(Note: For K = 0.5 V/m, we get, E = 1.08V (reasonable value)]

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