InterviewSolution
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InterviewSolution
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A prism of refracting angle `60^(@)` is made with a material of refractive index `mu`. For a certain wavelength of light, the angle of minimum deviation is `30^(@)`. For this, wavelength the value of refractive index of the material isA. `1.820`B. 1.503C. 1.414D. 1.231 |
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Answer» Correct Answer - C `A = 60^(@), delta_(m) = 30^(@), mu = ?` `mu = (sin((A+delta_(m))/(2)))/(sin((A)/(2))) = (sin((60+30)/(2)))/(sin((60)/(2)))` `= (sin 45)/(sin 30) = sqrt(2) = 1.414` |
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