InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A projectile aimed at a mark, which is in the horizontal plane through the point of projection, falls a cm short of it when the elevation is `alpha` and goes b cm far when the elevation is `beta`. Show that, if the speed of projection is same in all the cases the proper elevation is `1/2 sin^(-1) [(bsin2alpha+asin2beta)/(a+b)]` . |
|
Answer» Correct Answer - A `R - a = (u^2 sin 2 alpha)/g` Multiplying with b we have, `bR - ab = (bu^2 sin 2alpha)/g`………..(i) `R + b = (u^2sin2beta)/g` Multiplying with a we have, `aR + ab = (au^2sin 2beta)/g` ……..(ii) Adding Eqs. (i) and (ii) and by putting `R = (u^2sin 2theta)/g,` we get the result. |
|