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A proton has kinetic energy `E = 100 keV` which is equal to that of a photo is `lambda_(1)` . The ratio of `k_(2) // lambda_(1) ` is proportional toA. `E^(2)`B. `E^(1//2)`C. `E^(-1)`D. `E^(-1//2)` |
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Answer» Correct Answer - D For photon, `lambda_(2) = (hc)/(E )`…(i) For proton , P = sqrt(2mE)` `lambda_(1) = (h)/(P) = (h)/(sqrt(2mE)) ` …(ii) `(lambda_(2))/( lambda_(1)) = (hc)/(E xx (h)/(sqrt(2mE))) prop E^(1//2)` |
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