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A proton is about `1840` times heavier than an electron. When it is accelerated by a potential difference of `1 kV`. Its kinetic energy will beA. `1840 keV`B. `1//1840 keV`C. `1 keV`D. `920 keV` |
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Answer» Correct Answer - C Kinetic energy of proton `K = eDeltaV = e xx 10^(3)V = 1keV`. |
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