A pulse travelling on a string is represented by the function y=a^3/((x-vt)^2+a^2)` where a=5 mm and v=20 cms^-1. Sketch the shape of the string at t=0, 1 s and 2s. Take x=0 in the middle of the string.

A pulse travelling on a string is represented by the function y=a^3/((

1.	A pulse travelling on a string is represented by the function y=a^3/((x-vt)^2+a^2)` where a=5 mm and v=20 cms^-1. Sketch the shape of the string at t=0, 1 s and 2s. Take x=0 in the middle of the string.
Answer» Correct Answer - A The pulse is given by `y=[((a)^3)/([(x-vt)^2+a^2)])]` `a=5mm` `=0.5cm` `v=20cm/s` At `t=0s, y=a^3/((x^2+a^2))` The graph between y and x can be plotted by talking different vaues of x. (left as excercse for the studen). ltbr.gt similarly at t=1 s, `y=a^3/({(x-v)^2+a^2])` and at t=2s, y=a^3/({(x-2v)^2+a^2})`

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A pulse travelling on a string is represented by the function y=a^3/((x-vt)^2+a^2)` where a=5 mm and v=20 cms^-1. Sketch the shape of the string at t=0, 1 s and 2s. Take x=0 in the middle of the string.

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