Two waves are smultaneously passing through a string. The equation of the waves are given by `y_1=A_1sink(x-vt)` and `y_2=A_2sink(x=vt+x_0)` where the wave number `k=6.28 cm^-1 and x_0=o1.50c. The ampitudes of `A_1=5.0mm and A_2=4.0mm. find the phase difference between the waves and the amplitude of the resulting wave.

Two waves are smultaneously passing through a string. The equation of

1.	Two waves are smultaneously passing through a string. The equation of the waves are given by `y_1=A_1sink(x-vt)` and `y_2=A_2sink(x=vt+x_0)` where the wave number `k=6.28 cm^-1 and x_0=o1.50c. The ampitudes of `A_1=5.0mm and A_2=4.0mm. find the phase difference between the waves and the amplitude of the resulting wave.
Answer» The phase of the first wave is `k(x-vt)` and of the second is `k(x-vt+x_0)` The phase difference is therefore, `delta=k x_0=(6.28cm^-1)(1.50cm)=2pixx1.5=3pi` The waves satisfy the condition of destructive interference. The amplitude of the resulting wave is given by `\|A_1-A_2\|=5.0mm-4.0mm=1.0mm`.

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