InterviewSolution
Saved Bookmarks
| 1. |
A string of length 40 cm and weighing 10 g is attached to a spring at one end and to a fixed wall at the other end. The spring has a spring constant of `160 N m^-1` and is stretched by 1-0 cm. If a wave pulse is produced on the string near the wall, how much time will it take to reach the spring ? |
|
Answer» L=40 cm, mass=10gm ………mass per unit length `=10/40=1/4(gm/cm)` `Spring costant=k=160N/m` Deflection =x=1cm` `=0.01m` `rarr T=kx=160x0.01` `=1.6N=6xx10^4 dyne` Again `v=sqrt((T/m)0=sqrt(((16x10^4)/(1/4)))` `=8xx10^2cm/s=800cm/s` `:. time taken by the pulse to reach the spring. `t=40/800=1/20=0.05sec` |
|