1.

A pump is used to lift 500 kg of water from a depth of 80 m in 10 s .Calculate : (a)the work done by the pump . (b)the power at which the pump works,and (c )the power rating of the pump if its efficiency is 40% (Take g =10 m s^(-2)) [Hint :Efficiency=("use power")/("power input")]

Answer»

Solution :(a) `4xx10^(5)J` (B)40 KW (c )100 kW


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