Saved Bookmarks
| 1. |
A pure inductor of 25 mh is connected to a 220 v and 50 hz frequncy fi d the inductive reactance and rms current of the circuit |
|
Answer» The INDUCTIVE reactance of the CIRCUIT is equal to 2.5π ohm. The rms current flowing in the circuit is equal to 19.8 A. L = 25 mH f = frequency of AC = 50 Hz X(L) = inductive reactance of the circuit = L× 2πf = 25 × (10)^-3 × 50× 2π = 2.5π ohm RMS VOLTAGE of the circuit = peak voltage of the circuit / √2 = 220/√2 The RMS current of the circuit = RMS voltage / inductive reactance of the circuit => 220/(2.5π × √2) => 19.8 A |
|