a race car accleration on a straight road from rest to a speed of 180k

1.	a race car accleration on a straight road from rest to a speed of 180kmhin 25s. assuming uniform accleration of the car throughtout,find the distance coveredin this time.
Answer» Answer: $\sf{The \ <klux>DISTANCE</klux> \ covered \ is \ 625 \ m}$ Given: Initial velocity (u)=0...[as car was in rest] FINAL velocity (v)= 180 km/hr Time=25 s To find: The distance cover by the car in till it's final velocity is 180 km/hr Solution: Final velocity (v)=180 km/hr >> 1 km=1000 m and 1 hr=3600 second $\therefore$ Final velocity (v)=180000/3600=50 m/s $\boxed{\sf{a=\dfrac{v-u}{t}}}$ $\sf{\therefore{Acceleration =\dfrac{50-0}{25}}}$ $\therefore$ Acceleration=2 m/s² According to the third equation of MOTION. $\boxed{\sf{v^{2}=u^{2}+2as}}$ $\sf{50^{2}=0^{2}+2(2)(s)}$ $\sf{\therefore{2500=4\times \ s}}$ $\sf{\therefore{s=\dfrac{2500}{4}}}$ $\sf{\therefore{s=625 \ m}}$ $\sf\purple{\tt{\therefore{The \ distance \ covered \ is \ 625 \ m}}}$