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A radioactive element is disintegrating having half-life 6.93 s. The fractional change in number of nuclei of the radioactive element during 10 s isA. (a) 0.37B. (b) 0.63C. (c) 0.25D. (d) 0.50 |
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Answer» Correct Answer - B `lambda=(1n2)/(t_(1//2))=0.693/6.93=1/10sec^-1` `N=N_0e^(-lambdat)` `:.N/N_0=e^(-lambdat)=e^(-(1/10)(10))` `=e^-1~~0.63` |
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