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A radioactive species undergoes decay for time `t` where `t = 4t_(1//2)` . The average life `(T)` of species can therefore be given by:A. `2t` in `2 = T`B. `4t` in `2 = T`C. `T = (t)/(4 "In" 2)`D. `T = (t)/(2 "In" 2)` |
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Answer» Correct Answer - `(c)` `T = (1)/(lambda) = (t_(1//2))/(0.693) = (t)/(4xx0.693) = (t)/(4 "in" 2)` |
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