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A radioactive substance contains `10^15` atoms and has an activity of `6.0xx10^11` Bq. What is its half-life? |
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Answer» Correct Answer - A::C `R_0=lambdaN_0` `6.0xx10^11=lambda(10^15)` `:.` `lambda=6.0xx10^(-4)s` `t_(1//2)=(1n2)/lambda=(0.693)/(6.0xx10^-4)` `=1.16xx10^3s` |
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