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A radioative sample emit `n beta` - particle is `2` sec , in next `5 eV` ` sec it emit ` 0.75 n beta`- particle , what is the mean life of the sample? |
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Answer» Correct Answer - B::C::D `lambda = (log_(e)(A_(0))/(A)/(t) = (1)/(2) log_(e) (n)/(0.75n)` `rArr Mean Life = (1)/(lambda) = (2)/(log_(e) 4 //3)` |
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