1.

A radioative sample emit `n beta` - particle is `2` sec , in next `5 eV` ` sec it emit ` 0.75 n beta`- particle , what is the mean life of the sample?

Answer» Correct Answer - B::C::D
`lambda = (log_(e)(A_(0))/(A)/(t) = (1)/(2) log_(e) (n)/(0.75n)`
`rArr Mean Life = (1)/(lambda) = (2)/(log_(e) 4 //3)`


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