

InterviewSolution
Saved Bookmarks
1. |
A railway engine weighing 40 metric ton is travelling along a level track at a speed of `54 km H^(-1)` What additional power is required to maintain the same speed up an incline of 1 in 49 Take `g = 9.8 m//s^(2)` and `m u = 0.1`. |
Answer» Here , `m = 40` metric ton ` = 40 xx 10^(3) kg` `upsilon 54 km//h = (54 xx 1000) /( 60 xx 60 ) m //s = 15 m//s`, `g = 9.8 m // s^(2)` `mu = 0. 1 , sin theta = 1//49 , (P_(2) - P_(2) ) = ? ` On a level track , `P_(1) = mu mg xx upsilon = 0.1 xx 4 xx 10^(4) xx 9.8 xx 15` `5.88 xx 10^(5) "watt"` Up the incline , ` P_(2) = mg (sin theta + mu cos theta) xx upsilon` ` 4 xx 10^(4) xx 9.8 ((1)/(49) + 0.1 xx 1 ) xx 15 ` ` 7 .08 xx 10^(5) W ` Additional power required ` = P_(2) - P_(1) = (7 .08 - 5 .88 ) 10^(5) W ` ` = 1.20 xx 10^(5) W = 120 k W ` . |
|