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A rain drop of radius 0.5 mm has a terminal velocity in air `2 ms^(-1)` . The viscosity of air is `18 xx 10^(-5)" dyne "cm^(-2)s` . Find the viscous force on the rain drop.

Answer» Here, `r = 0.5 mm = 0.05 cm, upsilon = 2 ms^(-1) = 200 cm//s , eta = 18 xx 10^(5)" dyne "cm^(-2) s, F=?`
Now, `F= 6 pi eta r upsion = 6 xx 22/7 xx 18 xx 10^(-5) xx 0.05 xx 200 = 0.034 dyn es`.


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