A ray of light enters into benzene frora air. If the rofractive index

1.	A ray of light enters into benzene frora air. If the rofractive index of benzene is 1.50, by what percent does the speedof light reduce on entering the benzene?
Answer» Refractive Index = Speed of light in Air / Speed of light in medium Speed of light in medium = Speed of light in air / Refractive index => Speed of light in medium = 3 × 10⁸ / 1.5 => Speed of light in medium = 2 × 10⁸ m/s So, Percentage Change = ( Change in Speed / Speed of light in air ) * 100 => Change in Speed = 3 × 10⁸ - 2 × 10⁸ => Change in speed = 10⁸ ( 3 - 2 ) = 10⁸ => Percentage change = ( 10⁸ / 3 × 10⁸ ) * 100 => Percentage change = ( 1 / 3 ) * 100 => Percentage change = 33.34 % This is the required answer

A ray of light enters into benzene frora air. If the rofractive index of benzene is 1.50, by what percent does the speedof light reduce on entering the benzene?

Answer»

Refractive Index = Speed of light in Air / Speed of light in medium

Speed of light in medium = Speed of light in air / Refractive index

=> Speed of light in medium = 3 × 10⁸ / 1.5

=> Speed of light in medium = 2 × 10⁸ m/s

So, Percentage Change = ( Change in Speed / Speed of light in air ) * 100

=> Change in Speed = 3 × 10⁸ - 2 × 10⁸

=> Change in speed = 10⁸ ( 3 - 2 ) = 10⁸

=> Percentage change = ( 10⁸ / 3 × 10⁸ ) * 100

=> Percentage change = ( 1 / 3 ) * 100

=> Percentage change = 33.34 %

This is the required answer

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