A ray of light travelling in glass `(mu_g=3//2)` is incident on a horizontal glass-air surface at the critical angle `theta_C.` If a thin layer of water `(mu_w=4//3)` is now poured on the glass-air surface. At what angle will the ray of light emerges into water at glass-water surface?

A ray of light travelling in glass `(mu_g=3//2)` is incident on a hori

1.	A ray of light travelling in glass `(mu_g=3//2)` is incident on a horizontal glass-air surface at the critical angle `theta_C.` If a thin layer of water `(mu_w=4//3)` is now poured on the glass-air surface. At what angle will the ray of light emerges into water at glass-water surface?
Answer» Correct Answer - A::C::D `sin theta_C=1/mu_1=2/3` Now, `u_1sini_1=u_2sini_2` or `mu_1sin theta_C=mu_2sin theta` `:. (3/2)(2/3) =(4/3)sin theta` or ` theta=sin^-1(3/4)`

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A ray of light travelling in glass `(mu_g=3//2)` is incident on a horizontal glass-air surface at the critical angle `theta_C.` If a thin layer of water `(mu_w=4//3)` is now poured on the glass-air surface. At what angle will the ray of light emerges into water at glass-water surface?

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