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A Ray of light while passing through a prism suffers a minimum deviation of 40, calculate the RI fo the material of prism if the angle is 60. [ given: sine 50= 0.7660, sine 30= 0.5] |
| Answer» F deviation is 37.2° and ANGLE of incidence is 48.6° For a PRISM, refractive index μ is given as: μ = [sin ([A + δ]/2) ] / sin (A/2) A is the angle of prism = 60° and δ is the angle of deviation. and we KNOW μ = 1.5. So, ⇒ [sin ([60 + δ]/2) ] / sin (60/2) = 1.5 ⇒ [sin ([60 + δ]/2) ] = 1.5 × 0.5 = 0.75 ⇒ ([60 + δ]/2) = sin⁻¹ (0.75) = 48.6° ⇒ 60° + δ = 2(48.6°) = 97.2° ⇒ δ = 97.2° - 60° = 37.2° Angle of deviation is 37.2°. So, angle of incidence i = (A + δ)/2 = (60° + 37.2°)/2 = 48.6°MARK ME AS BRAINLIEST | |