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InterviewSolution
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A reaction is first order in `A` secod order in `B`: (i) write differential rate equation. (ii) How is the rate affected when the concentration of `B` is tripled ? (iii) How is the rate affected when the concentration of both `A` and `B` is doubled? |
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Answer» (i) The differential rate equation will be `-(d [R])/("dt") = k [A] [B]^(2)` (ii) If the concentration of B is increased three times , then `-(d[R])/("dt") = k[A] [3B]^(2)` = `9* k [ A] [B]^(2)` Therefore , the rate of reaction will increase 9 times (iii) When the concentrations of both A and B are doubled , `-(d [R])/("dt") = k[A] [B]^(2)` = `k[2A][2B]^(2)` = `8*k [A][B]^(2)` Therefore , the rate of reaction will increase 8 times . |
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