A reaction rate constant is given by `k = 1.2 xx 10^(14) e^(-(25000//RT)) sec^(-1)` . It meansA. log k versus log T will give a straight line with slope as `- 25000`B. log k versus T will give a straight line with slope as `- 25000`C. log k versus log 1/T will give a straight line with slope `-25000`D. log k versus 1/T will give a straight line

A reaction rate constant is given by `k = 1.2 xx 10^(14) e^(-(25000//R

1.	A reaction rate constant is given by `k = 1.2 xx 10^(14) e^(-(25000//RT)) sec^(-1)` . It meansA. log k versus log T will give a straight line with slope as `- 25000`B. log k versus T will give a straight line with slope as `- 25000`C. log k versus log 1/T will give a straight line with slope `-25000`D. log k versus 1/T will give a straight line
Answer» Correct Answer - d According to the Arrhenius equation a straight line is to be obtained by plotting the logarithm of the rate constant of a chemical reaction (log k) against 1/T.

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