InterviewSolution
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InterviewSolution
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A reaction `SO_(2)Cl_(2) to SO_(2)+ Cl_(2)` is first order reaction with half life period `3.15 xx 10^(4)`s at `320^(@)`C. What percentage of `SO_(2)Cl_(2)` would be decomposed on heating at `320^(@)`C for 90 minutes? |
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Answer» `k=0.693/t_(1//2)=0.693/(3.15 xx 10^(4)s)= 2.2 xx 10^(-5)s^(-1)` For the first order reaction, `t=2.303/k log a/(a-x)` `k=2.2 xx 10^(-5)s^(-1)`, t=90 min `=90 xx 60=5400s` `(5400s) = 2.303/(2.2 xx 10^(-5)s^(-1)) log a/(a-x)` (5400s) = `(2.303)/(2.2 xx 10^(-5)s^(-1))log (a/a-x)` `loga/(a-x) = (5400s)xx(2.2 xx 10^(-5)s^(-1))/(2.303) = 0.0516` `a/(a-x) = "Antilog" 0.0516=1.126` or `a=1.126a-1.126x` `0.126a = 1.126x` or `x//a = 0.126/1.126 = 0.112` or `%`of `SO_(2)Cl_(2)` decompoed `= 0.112 xx 100 = 11.2%` |
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