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A reaction that is of the first order with respect to reactant A has a rate constant `6 "min"^(-1)`. If we start with `[A] = 0.5 "mol" 1^(-1)`, when would `[A]` reach the value `0.05 mol 1^(-1)`A. 0.384 minB. 0.15 minC. 3 minD. 3.84 min |
Answer» Correct Answer - a We know that for first order kinetics `k = (2.303)/(t)` log `(a)/(a-x)` `(a-x) = 0.05` mol `l^(-1) , 6 = (2.303)/(t)` log `(0.5)/(0.05)` or `t = (2.303)/(6)` log `(0.5)/(0.05) = (2.303)/(6) = 0.384` min . |
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