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A reaction, which is second order,has a rate constant of `0.002 L mol^(-1)s^(-1)`. If the initial cond. Of the reactant is `0.2M`. How long will it take for the concentration to become `0.0400M` ?A. `1000s `B. `400 s`C. `200 s`D. `10,000s` |
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Answer» Correct Answer - 4 `(1)/(C_(1))=(1)/(C_(0))+KL` `(1)/(0.04)=(1)/(0.02)+0.002xxt.` `rArr" "25=5+0.002xxt` `rArr" "t=(20)/(2xx10^(-3))=10,000sec.` |
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