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A rectangular wooden block has massof 4 kg .The length ,breadth and height of this wooden block are 50 cm,25 cm and 10 cm ,respectively .Find the pressure on the table top: ( a)When the wooden bock is kept with its surface measuring 50 cm xx 25 cm on the table . (b) When the woodenblock is kept with its sufarce measring 25 cm xx 10 cmon the table . (Assume : Acceleration due to gravity , (g=10 m/s^(2)) |
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Answer» Solution :HereMass of WOODEN BLOCK m= 4kg Acceleration dur to gravity ,`g=10 m//s^(2)` Weightof wooden block ` W=mxxg ` `=4xx10` =40 N since weight is a force,so we can say that the force excerted by the wooden block on the table top is 40 N .We will now calculate the pressure in the two cases.  (a) In the first case :Force = 40 N(Calculated above) `AREA =50 cm xx 25 cm` `=(50)/(100) m xx (25)/ (100 )` `=0.5 m xx 0.25 m` ` = 0.125 m^(2)` Now Pressure ` =("Force")/("Area")` `=40/0.125` `=320 Nm^(2)`(or 320) Thus the pressure exerted by the wooden block on table top when kept on its face measuring `50 cm xx 25 cm ` is 320 `Nm^(-2)` of 320 pascals (see Figure 44) (b) In the second case : Force = 40 N(Same as above) Area `= 25 cm xx 10 cm` `=25 /100 mxx10/100 m` `=0.25 m xx 0.1 m` `=0.025 m^(2)` `Pressre = (Force)/(Area)` `=(40)/(0.025)` ` =1600 N m^(-2)` (or 1600) Thus the pressure exerted by the wooden block on table top when kept on its face measuring `25 cm xx 10 cm ` is 1600 N `m^(-2)` of 1600 pascals (see figure 45) 
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