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                                    A red bulb and violet bulb of equal power emits `n_(R )` and `n_(v)` number of photons in a given time, thenA. `n_(R ) = n_(v)`B. `n_(R ) gt n_(v)`C. `n_(R ) lt n_(v)`D. `n_(R ) ge n_(v)` | 
                            
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Answer» Correct Answer - B We know that, `E-(hc)/(lambda)` Let, power=P then, energy in time t `nE=Pt" and "n=(Pt)/(E)=(Ptlambda)/(hc)` `therefore" "n_(R)=(Ptlambda_(R))/(hc)" "...(i)` `n_(v)=(Ptlambda_(v))/(hc)" "....(ii)` Dividing Eq. (i) by Eq. (ii), we get `(n_(R))/(n_(v))=(lambda_(R))/(lambda_(v))` We know, `lambda_(R) gt lambda_(v)` `n_(R) gt n_(V)`  | 
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