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A refrigerator is to maintain eatables kept inside at `9^(@)C`, if room temperature is `36^(@)C`. Calculate the cofficient of performance. |
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Answer» Temperature inside the refrigerator, `T_(1)=9^(@)C=282K` Room temperature, `T_(2) = 36^(@)C = 309 K` Coefficient of performance`=(T_(1))/(T_(2)-T_(1))` `=(282)/(309-282)` `=10.44` Therefore, the coefficient of performance of the given refrigerator is 10.44. |
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