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A refrigerator works between `4^(@)C` and `30^(@)C`. It is required to remove `600 calories` of heat every second in order to keep the temperature of the refrigerator space constant.The power required is (Take `1calorie= 4.2 J`)A. `23.65W`B. `236.5W`C. `2365W`D. `2.365W` |
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Answer» Correct Answer - B Here,`T_(2)= 4^(@)C= 4+273= 277K` `T_(1)= 30^(@)C=30+273= 303K` `Q_(2)= 600cal//s= 600xx4.2J//s` `P=?` As `COP=(Q_(2))/W= (T_(2))/(T_(1)-T_(2))` `:. W=(Q_(2)(T_(1)_T_(2)))/(T_(2))= (600xx4.2(303-277))/(277)` `W= 236.5 J//s= 236.5 "Watt"`. |
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