1.

A resistance of 3 Ω is connected in parallel to a galvanometer of resistance 297 Ω. Find the fraction of the current passing through the galvanometer.

Answer»

Data : G = 297 Ω, S = 3 Ω

Ig\(\cfrac{S}{S+G}\). I

∴ \(\cfrac{I_g}I\) = \(\cfrac{S}{S+G}\) = \(\cfrac{3}{3+297}\) = \(\cfrac{3}{300}\) = 0.01

This is the fraction of the current through the galvanometer.

[Note: The fraction of the current through the shunt

\(\cfrac{I_s}I\) = 1 - 0.01 = 0.99]



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