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A resistance of 3 Ω is connected in parallel to a galvanometer of resistance 297 Ω. Find the fraction of the current passing through the galvanometer. |
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Answer» Data : G = 297 Ω, S = 3 Ω Ig = \(\cfrac{S}{S+G}\). I ∴ \(\cfrac{I_g}I\) = \(\cfrac{S}{S+G}\) = \(\cfrac{3}{3+297}\) = \(\cfrac{3}{300}\) = 0.01 This is the fraction of the current through the galvanometer. [Note: The fraction of the current through the shunt = \(\cfrac{I_s}I\) = 1 - 0.01 = 0.99] |
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