1.

A resistor of 10Ω connected across a cell of emf i2 V, draws the current of 1.1A.Find the internal resistance of the cell.4,

Answer»

12/(10+r) = 1.1

So, 11+1.1r = 12

1.1 r = 1

Therefore, internal resistance r = 1/1.1 =0.90909 ohms



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