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InterviewSolution
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A reversible heat engine A(based on carnot cycle ) absorbs heat from a reservoir at 1000 K and rejects heat to a reservoir at `T_(2)` . A second reserviour at `T_(2)` and rejects energy to a reservoir at 360 K . If the efficiencies of engines A and B are the same then the temperature `T_(2)`is .A. 680 KB. 640 KC. 600 KD. None |
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Answer» Correct Answer - C For A `eta_(1)= 1- (T_(2))/(1000)` For B `eta_(2) = 1 -(360)/(T_(2))` `1- (T_(2))/(1000)= 1 -(360)/(T_(2))` `T_(2)= 600K` |
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