A ring of mass `3kg` is rolling Without Slipping with linear velocity `1 ms^(-1)` on a smooth horizontal surface. A rod of same mass is fitted along its one diameter. Find total kinetic energy of the system (in `J`).

A ring of mass `3kg` is rolling Without Slipping with linear velocity

1.	A ring of mass `3kg` is rolling Without Slipping with linear velocity `1 ms^(-1)` on a smooth horizontal surface. A rod of same mass is fitted along its one diameter. Find total kinetic energy of the system (in `J`).
Answer» Correct Answer - 5 `K=K_(R)+K_(T)=1/2[mR^(2)+((2R)^(2))/12][V/R]^(2)+1/2(2m)V^(2)` `=5/3Mv^(2)=5/3(3)(1)^(2)=5J`

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A ring of mass `3kg` is rolling Without Slipping with linear velocity `1 ms^(-1)` on a smooth horizontal surface. A rod of same mass is fitted along its one diameter. Find total kinetic energy of the system (in `J`).

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