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A ring of mass `m` and radius `R` is rolling down on a rough inclined plane of angle `theta` with horizontal. Plot the angular momentum of the ring about the point of contact of ring and the plane as a function of timeA. B. C. D. |
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Answer» Correct Answer - D `L=(mg sin theta)Rt`, since , `tau=(DeltaL)/(Deltat)`, so, `L=tau(Deltat)` The curve between `L` and time `t` will be a straight line. |
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