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A rod of length (f/2) is placed along theaxis of a concave mirror of focal length f. If the near ead ofthe real image formed by the mirror just touches thefar end of the rod, find its magnification.

Answer»

Solution :(i) DRAW a ray diagram representing the given situation.
Let AB be theobject and A be thenear END of the object and Bbe the far end of theobject.
Let A'B' be the image formed.
As B' COINCIDES with the end B at the centre of CURVATURE,
`:. ` the distance of B from the mirror = 2f.
Let the length of the object be `f/2`.
The end A is at a distance of `(2f-f/2)`.
By using`1/f = 1/v - 1/u`,
Determine the distance of A'B', from the mirror and find the length of the image. u= 2f - d
The magnification , `m = ("length of the image")/("length of the object") `
(ii) m = 2


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