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A rod of length (f/2) is placed along theaxis of a concave mirror of focal length f. If the near ead ofthe real image formed by the mirror just touches thefar end of the rod, find its magnification. |
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Answer» Solution :(i) DRAW a ray diagram representing the given situation. Let AB be theobject and A be thenear END of the object and Bbe the far end of theobject. Let A'B' be the image formed. As B' COINCIDES with the end B at the centre of CURVATURE, `:. ` the distance of B from the mirror = 2f. Let the length of the object be `f/2`. The end A is at a distance of `(2f-f/2)`. By using`1/f = 1/v - 1/u`, Determine the distance of A'B', from the mirror and find the length of the image. u= 2f - d The magnification , `m = ("length of the image")/("length of the object") ` (ii) m = 2 |
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