A rod of mass `m` spins with an angular speed `omega=sqrt(g/l)`, Find its a. kinetic energy of rotation. b. kinetic energy of translation c. total kinetic energy.

A rod of mass `m` spins with an angular speed `omega=sqrt(g/l)`, Find

1.	A rod of mass `m` spins with an angular speed `omega=sqrt(g/l)`, Find its a. kinetic energy of rotation. b. kinetic energy of translation c. total kinetic energy.
Answer» Kinetic enegy of rotation `K_("rotational") = 1/2 I_(C)omega^(2)` `=1/2 ((ml^(2))/12)(sqrt(g)/l)^(2)=1/24mlgl` b Kinetic energy of translation, `K_("rotational")=1/2 mv_(C)^(2)` `=1/2 m[(omegal/2)^(2)]=1/2 m[sqrt(g/l)xxl/2]^(2)=1/3mgl` c. total kinetic energy `K_("total")=K_("translational")+K_("rotational")` `=1/6mgl=1/2I_(P)omega^(2)=1/2[(ml^(2))/2][sqrt(g/l)]^(2)=1/6mgl`

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A rod of mass `m` spins with an angular speed `omega=sqrt(g/l)`, Find its a. kinetic energy of rotation. b. kinetic energy of translation c. total kinetic energy.

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