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A rope of length L and mass M is hanging from a rigidsupport. The tension in the rope at a distance x from therigid support is:L-x(a) Mg(d) 스 Mg |
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Answer» if the chain is held vertically downward two forces will be acting along the surface of chainone of them is the mass of the chain that is mg acting vertically downward and other is the tension of chain acting vertically upward and canceling the effect of mass pulling it downwardsince acceleration is zero soF(net)=0so mass of chain is m=(L-x)T=mgm=(L-x)/L*mT=[(L-x)/L]*Mg |
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