A rope of mass `0.5kg` is pulling a block of mass `10kg` under the action of force of `31.5N` If the block is resting on a smooth horizontal surface calculate the force of reaction exerted by the block on the rope .

A rope of mass `0.5kg` is pulling a block of mass `10kg` under the act

1.	A rope of mass `0.5kg` is pulling a block of mass `10kg` under the action of force of `31.5N` If the block is resting on a smooth horizontal surface calculate the force of reaction exerted by the block on the rope .
Answer» Correct Answer - `30N` . Total mass `= m + M = 0.5 + 10 = 10.5 kg` `F= 31.5 N` `:.a = (F)/((m + M)) = (31.5)/(10.5) = 3m//s^(2)` Force of reaction exerted block on the rope `R = M xx a = 10 xx 3 = 30 N` .

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A rope of mass `0.5kg` is pulling a block of mass `10kg` under the action of force of `31.5N` If the block is resting on a smooth horizontal surface calculate the force of reaction exerted by the block on the rope .

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